Answer
$f^{-1}(x)=\sqrt[6]{x}$
Work Step by Step
$f(x)=x^{6}$ $,$ $x\ge0$
Rewrite this expression as $y=x^{6}$ and solve for $x$:
$y=x^{6}$
$x^{6}=y$
Take the sixth root of both sides:
$\sqrt[6]{x^{6}}=\sqrt[6]{y}$
$x=\sqrt[6]{y}$
Interchange $x$ and $y$:
$y=\sqrt[6]{x}$
The inverse of the original function is $f^{-1}(x)=\sqrt[6]{x}$