Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 218: 76

Answer

With $R(x)=0.15x-0.000002x^{2}$ and $C(x)=0.095x-0.0000005x^{2}$ the profit function can be written as $P(x)=R(x)-C(x)$ (a difference of two functions of x)

Work Step by Step

In the previous exercise, we found $R(x)=f(x)\cdot g(x)=(0.15-0.000002x)\cdot x$ $R(x)=0.15x-0.000002x^{2}$ The text gives us the cost function, $C(x)=0.095x-0.0000005x^{2}$ So, the profit function P(x) can be written as $P(x)=R(x)-C(x)$ $(P(x)=0.055x-0.0000015x^{2})$
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