Answer
With $R(x)=0.15x-0.000002x^{2}$ and $C(x)=0.095x-0.0000005x^{2}$
the profit function can be written as $P(x)=R(x)-C(x)$
(a difference of two functions of x)
Work Step by Step
In the previous exercise, we found
$R(x)=f(x)\cdot g(x)=(0.15-0.000002x)\cdot x$
$R(x)=0.15x-0.000002x^{2}$
The text gives us the cost function,
$C(x)=0.095x-0.0000005x^{2}$
So, the profit function P(x) can be written as
$P(x)=R(x)-C(x)$
$(P(x)=0.055x-0.0000015x^{2})$