Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 216: 1

Answer

$(f+g)(2)=8$ $(f-g)(2)=-2$ $(fg)(2)=15$ $(\displaystyle \frac{f}{g})(2)=\frac{3}{5}$

Work Step by Step

From the graphs, we read $f(2)=3,\quad g(2)=5.$ So, $(f+g)(2)=f(2)+g(2)=3+5=8$ $(f-g)(2)=f(2)-g(2)=3-5=-2$ $(fg)(2)=f(2)\cdot g(2)=3\cdot 5=15$ $(\displaystyle \frac{f}{g})(2)=\frac{f(2)}{g(2)}=\frac{3}{5}$
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