Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 216: 2

Answer

$f[g(x)],\ 12$

Work Step by Step

$f\circ g(x)=f[g(x)]$, so $f\circ g(2)=f[g(2)]=f[5]=12$
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