Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 188: 22


a)$\frac{-2h}{h+1}$ b) $\frac{-2h^2}{h+1}$

Work Step by Step

a) $g(0)=\frac{2}{0+1}=2$ $g(h)=\frac{2}{h+1}$ $\frac{2}{h+1}-2=\frac{-2h}{h+1}$ b) $\frac{\frac{-2h}{h+1}}{h-0}$ = ${\frac{-2h}{h+1}}\times\frac{1}{h}$ =$\frac{-2}{h+1}$
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