Answer
a) -16
b) -4
Work Step by Step
a) $g(-2)=(-2)^4-(-2)^3+(-2)^2=16+8+4=28$
$g(2)=(2)^4-(2)^3+(2)^2=16-8+4=12$
12-28=-16
b) $\frac{12-28}{2--2}=-4$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 188: 18
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