Answer
$y = \sqrt {9-x^2}$
Domain is [-3, 3]
Work Step by Step
$x^2 + y^2 = 9$
$y^2 = 9 -x^2$
$y = \sqrt {9-x^2}$ (positive since it is top half)
Domain is [-3, 3]
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 2 - Section 2.2 - Graphs of Functions - 2.2 Exercises - Page 169: 77
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