Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - 2.1 Exercises - Page 158: 84

Answer

(a) Respectively: $28.14 \space mi$ and $39.8 \space mi$ (b) 41.27 mi (c) 235.56 mi (d) 194.29 mi

Work Step by Step

(a) Substitute the values for $h$ into the function and use a calculator to find $D(h)$ in each case. Remember: $(r = 3960)$ $$D(0.1) = \sqrt {2r(0.1) + (0.1)^2}= 28.14$$ $$D(0.2) = \sqrt {2r(0.2) + (0.2)^2}= 39.8$$ (b) $1 \space mi = 5280 \space ft$ $h = 1135 \space ft \times \frac{1 \space mi}{5280 \space ft} = 0.215 \space mi$ $$D(0.215) = \sqrt {2r(0.215) + (0.215)^2}= 41.27$$ (c) $$D(7) = \sqrt {2r(7) + (7)^2}= 235.56$$ (d) $D(7) - D(0.215) = 235.56 - 41.27 = 194.29$
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