Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.2 - Finding Limits Algebraically - 13.2 Exercises - Page 913: 20

Answer

$ \frac{3}{5}$

Work Step by Step

$\frac{x^{2}+5x+4}{x^{2}+3x-4}$ Simplify $\frac{(x+4)(x+1)}{(x+4)(x-1)}$ Cancel out like terms $\frac{x+1}{x-1}$ Substitute x for -4 $\frac{(-4)+1}{(-4)-1}=\frac{(-3)}{(-5)}= \frac{3}{5}$
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