Answer
$0.33$
Work Step by Step
Use the function and the x-value provided by the table, calculate the function values as shown in the table.
Based on the completed table, the limit of function can be estimated to be $0.33$
Extra: prove algebraically, $\lim_{x\to 1}=\frac{x-1}{x^3-1}=\lim_{x\to 1}=\frac{x-1}{(x-1)(x^2+x+1)}=\lim_{x\to 1}=\frac{1}{x^2+x+1}=\frac{1}{1^2+1+1}=\frac{1}{3}$
