Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.1 - Finding Limits Numerically and Graphically - 13.1 Exercises - Page 904: 3

Answer

$\lim _{x\rightarrow 0}\dfrac {2^{x}-1}{x}\approx 0.693$

Work Step by Step

As we see if x getting close to 0 (seen in graph and table) $\lim _{x\rightarrow 0}\dfrac {2^{x}-1}{x}\approx 0.693$
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