Answer
$f'\left( 16\right) =\dfrac {1}{2}\times \left( 16\right) ^{-\dfrac {1}{2}}=\dfrac {1}{8}=0.125$
Work Step by Step
$f\left( x\right) =\sqrt {x}=\left( x\right) ^{\dfrac {1}{2}}\Rightarrow f'\left( x\right) =\dfrac {1}{2}\times \left( x\right) ^{\dfrac {1}{2}-1}=\dfrac {1}{2}\times x^{\dfrac {-1}{2}}\Rightarrow f'\left( 16\right) =\dfrac {1}{2}\times \left( 16\right) ^{-\dfrac {1}{2}}=\dfrac {1}{8}$
