Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Review - Exercises - Page 942: 15


$\lim _{x\rightarrow 3 ^{-}}\dfrac {x-3}{\left| x-3\right| }=-1$

Work Step by Step

$x < a\Rightarrow \left| x-a\right| =a-x\Rightarrow \lim _{x\rightarrow 3 ^{-}}\left| x-3\right| =\left( 3-x\right) $ $\lim _{x\rightarrow 3 ^{-}}\dfrac {\left( x-3\right) }{\left| x-3\right| }=\dfrac {x-3}{3-x}=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.