Answer
$\lim _{x\rightarrow 0}\dfrac {\sin 2x}{x}=2$
Work Step by Step
As we see from graph and table when x gets close to zero
$\lim _{x\rightarrow 0}\dfrac {\sin 2x}{x}=2$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 13 - Review - Exercises - Page 941: 4
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