Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Review - Exercises - Page 941: 1

Answer

$\lim _{x\rightarrow 2}f\left( x\right) =\dfrac {x-2}{x^{2}-3x+2}=1$

Work Step by Step

As we see from table and graph when x gets close to 2 $f\left( x\right) =\dfrac {x-2}{x^{2}-3x+2}\rightarrow 1$
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