Answer
$\lim _{x\rightarrow 2}f\left( x\right) =\dfrac {x-2}{x^{2}-3x+2}=1$
Work Step by Step
As we see from table and graph when x gets close to 2
$f\left( x\right) =\dfrac {x-2}{x^{2}-3x+2}\rightarrow 1$
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