Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.5 - Mathematical Induction - 12.5 Exercises - Page 878: 20

Answer

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Work Step by Step

Step 1. Prove the statement is true when $n=1$: $3^2-1=8$ is divisible by 8, thus it is true for $n=1$. Step 2. Assume the statement is true when $n=k$: we have $3^{2k}-1$ is divisible by 8. We can assume $3^{2k}-1=8m$ or $3^{2k}=8m+1$ where $m$ is an integer. Step 3. Prove it is true for $n=k+1$: $3^{2k+2}-1=9\times3^{2k}-1=9(8m+1)-1=72m+8=8(9m+1)$ which is divisible by 8. Thus, the statement is also true for $n=k+1$ Step 4. Conclusion: with mathematical induction, we have proved that the statement is true for all natural numbers $n$.
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