Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.2 - Arithmetic Sequences - 12.2 Exercises - Page 858: 75

Answer

20 rows

Work Step by Step

The number of seats in a row form an arithmetic sequence with first term $a=15$ and common difference $d=3$. The sum of the first n terms (total seats in n rows) is $S_{n}=\displaystyle \frac{n}{2}[2a+(n-1)d]$ Given $S_{n}=870$, we find n. $870=\displaystyle \frac{n}{2}[2(15)+(n-1)3]$ $870=\displaystyle \frac{n}{2}(27+3n) \qquad/\times 2$ $1740=3n^{2}+27n$ $3n^{2}+27n-1740=0 \qquad/\div 3$ $n^{2}+9n-580=0$ Quadratic formula: $n=\displaystyle \frac{-9\pm\sqrt{81+2320}}{2}=\frac{-9\pm 49}{2}$ ...discarding the negative solution, $n=\displaystyle \frac{-9+49}{2}=20$ The theater has 20 rows.
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