Answer
$\$ 403,500$
Work Step by Step
The salaries form an arithmetic sequence with
$a=30,000$ and common difference $d=2300$.
After ten years, there will have been 9 raises.
His total eamings for a ten-year period are equal to
the sum of the first 10 terms of the arithmetic sequence:
$S_{n}=\displaystyle \frac{n}{2}[2a+(n-1)d]$
$S_{10}=\displaystyle \frac{10}{2}[2(30,000)+9(2300)]$
$=403,500$.
