Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 12 - Section 12.1 - Sequences and Summation Notation - 12.1 Exercises - Page 852: 83

Answer

(a) $S_n=S_{n-1}+2000=S_1+2000(n-1)$ (b) $S_5=38000$

Work Step by Step

(a) Step 1. The starting salary is $S_1=30000$, Step 2. With a raise of $2000$ every year, his salary in second year will be $S_2=S_1+1\times2000$, Step 3. His salary in third year will be $S_3=S_2+2000=S_1+2\times2000$ ... ... Step 4. Repeat the above process, his salary in $n$th year will be $S_n=S_{n-1}+2000=S_1+2000(n-1)$ (b) In his fifth year, with $n=5$, we can get $S_5=38000$ as shown in the figure where his salaries up to 12 years have been calculated.
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