Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.5 - Rotation of Axes - 11.5 Exercises - Page 823: 14

Answer

$Y=X$

Work Step by Step

Step 1. Identify the given quantities: equation $xy=x+y$, rotation $ \phi=\frac{\pi}{4}$ Step 2. Recall the formula for the transformation: $x=X\cdot cos\frac{\pi}{4} - Y\cdot sin\frac{\pi}{4}=\frac{\sqrt 2}{2}(X-Y)$, $y=-X\cdot sin\frac{\pi}{4}+Y\cdot cos\frac{\pi}{4}=\frac{\sqrt 2}{2}(-X+Y)$ Step 3. Plug-in the expressions above to the equation: $\frac{\sqrt 2}{2}(X-Y)\frac{\sqrt 2}{2}(-X+Y)=\frac{\sqrt 2}{2}(X-Y)+\frac{\sqrt 2}{2}(-X+Y)$ Step 4. Simply the above equation to get $-(X-Y)^2=\sqrt 2(0)=0$ which gives $Y=X$
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