Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 11 - Section 11.3 - Hyperbolas - 11.3 Exercises - Page 806: 42

Answer

$$\Rightarrow \frac{y^{2}}{36}-\dfrac {x^{2}}{324}=1$$

Work Step by Step

Equation of hyperbola with a format of $$\dfrac {y^{2}}{a^{2}}-\dfrac {x^{2}}{b^{2}}=1\left( a > 0,b > 0\right) $$ Vertices are $\left( 0,\pm a\right) $ Asymptotes are $y=\pm \dfrac {a}{b}x$ Given vertices $(0,\pm6)$ we find $a=6$ and given asymptotes $(\pm\frac{1}{3}x)$ we find $\dfrac{a}{b}=\frac{1}{3}$ $\Rightarrow b=18$ Then the equation will be $$\Rightarrow \frac{y^{2}}{36}-\dfrac {x^{2}}{324}=1$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.