Answer
$( \pm1,0)$
Work Step by Step
Step 1. Rewrite the second equation as $x^2=1-\frac{y^2}{9}$ and plug it into the first equation to get
$100(1-\frac{y^2}{9})+25y^2=100$ or $(25-\frac{100}{9})y^2=0$
Step 2. Solve the above equation to get $y=0$, back substitute into the first (or second) equation to get
$x^2=1-\frac{0^2}{9}$ or $x=\pm1$
Step 3. State the intersection points: $( \pm1,0)$
Step 4. Graph the equations and label the intersection points as shown.
