Answer
$(0, \pm2)$, see graph.
Work Step by Step
Step 1. Rewrite the first equation as $4x^2=4-y^2$ and plug it in the second equation to get
$(4-y^2)+9y^2=36$ or $8y^2=32$
Step 2. Solve the above equation to get $y=\pm2$, back substitute into the first (or second) equation to get
$4x^2=4-(\pm2)^2=0$ or $x=0$
Step 3. State the intersection points: $(0, \pm2)$
Step 4. Graph the equations and label the intersection points as shown.
