Answer
(a)
Vertex: $V(0,0)$
Focus: $F(\frac{1}{2},0)$
Directrix: $x=-\frac{1}{2}$
(b)
Work Step by Step
Equation of a parabola with horizontal axis and vertex at $(h,k)$:
$(y-k)^2=4p(x-h)$
$2x-y^2=0$
$2x=y^2$
$(y-0)^2=2(x-0)$
$h=0$
$k=0$
$4p=2$
$p=\frac{1}{2}$
Vertex: $V(h,k)=V(0,0)$
Focus: $F(p,0)=F(\frac{1}{2},0)$
Directrix: $x=-p=-\frac{1}{2}$
