Answer
(a)
Vertex: $V(0,0)$
Focus: $F(3,0)$
Directrix: $x=-3$
(b)
Work Step by Step
Equation of a parabola with horizontal axis and vertex at $(h,k)$:
$(y-k)^2=4p(x-h)$
$x=\frac{1}{12}y^2$
$y^2=12x$
$(y-0)^2=12(x-0)$
$h=0$
$k=0$
$4p=12$
$p=3$
Vertex: $V(h,k)=V(0,0)$
Focus: $F(p,0)=F(3,0)$
Directrix: $x=-p=-3$