Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.5 - Inverses of Matrices and Matrix Questions - 10.5 Exercises - Page 732: 41

Answer

$x= 126$ $y=-50$

Work Step by Step

Given: $2x + 5y = 2$ $-5x - 13y = 20$ Convert the linear system into a matrix equation: $A=\left[\begin{array}{ll} 2 & 5\\ -5 & -13 \end{array}\right],\qquad B=\left[\begin{array}{l} 2\\ 20 \end{array}\right],\quad X=A^{-1}B$ Find the inverse of A $ad-bc=2 * (-13) - (5)(-5)= -26 - (-25) = -1$ $A^{-1}=\frac{1}{-1}\cdot \left[\begin{array}{ll} -13 & -5\\ 5 & 2 \end{array}\right]$ $A^{-1}=\left[\begin{array}{ll} 13 & 5\\ -5 & 2 \end{array}\right]$ $X=\left[\begin{array}{ll} 13 & 5\\ -5 & 2 \end{array}\right]\left[\begin{array}{l} 2\\ 20 \end{array}\right]=\left[\begin{array}{l} 13(2) + 5(20)\\ -5(2) + 2(20) \end{array}\right]=\left[\begin{array}{l} 126\\ -50 \end{array}\right]$ $x= 126$ $y=-50$
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