Answer
$x=12,\quad y=-8$
Work Step by Step
$A=\left[\begin{array}{ll}
-3 & -5\\
2 & 3
\end{array}\right],\qquad B=\left[\begin{array}{l}
4\\
0
\end{array}\right],\quad X=A^{-1}B$
$ad-bc=-3(3)-(-5)(2)=1\neq 0$
$A^{-1}=(1)\cdot\left[\begin{array}{ll}
3 & 5\\
-2 & -3
\end{array}\right]$
$A^{-1}=\left[\begin{array}{ll}
3 & 5\\
-2 & -3
\end{array}\right]$
$X=A^{-1}B$
$X=\left[\begin{array}{ll}
3 & 5\\
-2 & -3
\end{array}\right]\left[\begin{array}{l}
4\\
0
\end{array}\right]=\left[\begin{array}{l}
3(4)+5(0)\\
-2(4)-3(0)
\end{array}\right]=\left[\begin{array}{l}
12\\
-8
\end{array}\right]$
$x=12,\quad y=-8$
