## Precalculus: Mathematics for Calculus, 7th Edition

Center $(1, 2)$ Radius = $3$ units
RECALL: The circle whose equation is of the form $(x-h)^2 + (y-k)^2=r^2$ has its center at $(h, k)$ and has a radius of $r$ units. Thus, the given circle has: center at (1, 2) radius = $\sqrt9 = 3$