## Precalculus: Mathematics for Calculus, 7th Edition

(a) To find the x-intercept(s) of the graph of an equation, we set __$y$__ equal to 0 and solve for __$x$__. So the x-intercept of $2y=x+1$ is $-1$ (b) To find the y-intercept(s) of the grapg of an equation we set __$x$__ equal to 0 and solve for __$y$__. So the y-intercept of $2y=x+1$ is $0.5$
(a) $2(0)=x+1$ subtract 1 from each side $0-1=x+1-1$ $x=-1$ (b) $2y=0+1$ isolate for y \$y=