Answer
(a) To find the x-intercept(s) of the graph of an equation, we set __$y$__ equal to 0 and solve for __$x$__. So the x-intercept of $2y=x+1$ is $-1$
(b) To find the y-intercept(s) of the grapg of an equation we set __$x$__ equal to 0 and solve for __$y$__. So the y-intercept of $2y=x+1$ is $0.5$
Work Step by Step
(a) $2(0)=x+1$
subtract 1 from each side
$0-1=x+1-1$
$x=-1$
(b) $2y=0+1$
isolate for y
$y=