Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 44: 89

$\dfrac{y}{\sqrt{3}+\sqrt{y}}=\dfrac{y\sqrt{y}-y\sqrt{3}}{y-3}$

$\dfrac{y}{\sqrt{3}+\sqrt{y}}$ Multiply both numerator and denominator by $\sqrt{3}-\sqrt{y}$ and simplify: $\dfrac{y}{\sqrt{3}+\sqrt{y}}=\Big(\dfrac{y}{\sqrt{3}+\sqrt{y}}\Big)\Big(\dfrac{\sqrt{3}-\sqrt{y}}{\sqrt{3}-\sqrt{y}}\Big)=\dfrac{y(\sqrt{3}-\sqrt{y})}{3-y}=...$ $...=\dfrac{y\sqrt{y}-y\sqrt{3}}{y-3}$