Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises - Page 44: 87

Answer

$-\frac{2(\sqrt 2-\sqrt 7)}{5}$

Work Step by Step

Multiply by conjugate radical: $\frac{2}{\sqrt 2+\sqrt 7}\times\frac{\sqrt 2-\sqrt 7}{\sqrt 2-\sqrt 7}$ Simplify using the Special Product Formula 1: $\frac{2(\sqrt 2-\sqrt 7)}{(\sqrt 2)^2-(\sqrt 7)^2}=\frac{2(\sqrt 2-\sqrt 7)}{2-7}=-\frac{2(\sqrt 2-\sqrt 7)}{5}$
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