Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises - Page 33: 22

Answer

$x^{2}-6x+17$

Work Step by Step

Expand the brackets, be mindful of the negative sign: $=4x^{2}-12x+20-3x^{2}+6x-3$ Collect the like terms: $=(4-3)x^{2}+(-12+6)x+(20-3)$ $=x^{2}-6x+17$
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