## Precalculus: Mathematics for Calculus, 7th Edition

$(3x^{2}+x+1)-(2x^{2}-3x-5)=x^{2}+4x+6$
$(3x^{2}+x+1)-(2x^{2}-3x-5)$ Change the sign of the terms in the second parentheses and simplify by combining like terms: $(3x^{2}+x+1)-(2x^{2}-3x-5)=3x^{2}+x+1-2x^{2}+3x+5$ $...=x^{2}+4x+6$