Answer
a) $a^{n}$ means "a" is the base and "n" is the exponent.
b) $a^{n}$ if "n" is a positive integer it means the base is multiplied by itself by the number of times corresponding integer "n" So $6^{5} = 6\times 6\times 6\times 6\times 6$.
c) $a^{-n}$ means the base is raised to a negative exponent. To solve this, the negative exponent in the numerator get moved to the denominator and become positive exponents so $\frac{1}{a^{n}}$ and thus an example is $3^{-2} = \frac{1}{3^{2}} = \frac{1}{9}$
d) $a^{n}$ if n is 0 means multiply the base by itself zero times and any base raised to the zero power results in 1. This is a special rule.
e) If "m" and "n" are positive integers, $a^{\frac{m}{n}}$ means raise it to the "mth" power and then take the "nth" root. So first raise the base to the power of the numerator which is "m" and then take the root of the denominator so $4^{\frac{3}{2}} = \sqrt[2]4^{3} = 8$
Work Step by Step
See above.
