Answer
$\sin (A+B)=\sin (A) \cos(B)+\cos(A) \sin(B)$
Work Step by Step
We know that the sum formula of two angles, let us say $a$ and $b$, is:
$sin (a+b) =\sin(a) \cos(b)+\cos(a) \sin(b)$
Therefore, our result is:
$\sin (A+B)=\sin (A) \cos(B)+\cos(A) \sin(B)$