Answer
$x^2+(y-3)^2=9$ in rectangular coordinates.
circle, center $(0,3)$, radius$=3$.
See graph.
Work Step by Step
$r=6sin\theta$,
$r^2=6r\ sin\theta$,
$x^2+y^2=6y$,
$x^2+(y-3)^2=9$ in rectangular coordinates.
It is a circle with center $(0,3)$, radius$=3$.
See graph.