Answer
$\frac{x^2}{4}-\frac{y^2}{16}=1$.
Work Step by Step
Based on the given graph, we can find the center $(0,0)$, transverse axis $x$-axis, $a=2,b=4$, Thus we have the equation $\frac{x^2}{4}-\frac{y^2}{16}=1$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.4 The Hyperbola - 9.4 Assess Your Understanding - Page 690: 40
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