Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.4 The Hyperbola - 9.4 Assess Your Understanding - Page 690: 39

Answer

$\frac{y^2}{36}-\frac{x^2}{9}=1$.

Work Step by Step

Based on the given graph, we can find the center $(0,0)$, transverse axis $y$-axis, $a=6,b=3$, 1. Thus we have the equation $\frac{y^2}{36}-\frac{x^2}{9}=1$.
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