Answer
horizontal asymptote $y=1$,
vertical asymptotes $x=\pm2$
Work Step by Step
For $y=\frac{x^2-9}{x^2-4}=\frac{(x+3)(x-3)}{(x+2)(x-2)}$, we can find:
a horizontal asymptote $y=1$ (ratio of the $x^2$ coefficients),
vertical asymptotes $x=\pm2$ (zero denominator),
and oblique asymptote: $none.$
