Answer
$(0,\pm3)$.
Work Step by Step
1. To find the x-intercept(s), let $y=0$, we have $9+4x^2=0$, there is no real solution to this equation.
2. To find the y-intercept(s), let $x=0$, we have $y^2=9$, thus we get: $y=\pm3$ or $(0,\pm3)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.4 The Hyperbola - 9.4 Assess Your Understanding - Page 689: 3
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