Answer
See graph, $x=y+1$
Work Step by Step
1. See graph for $(x,y)=(sec^2(t), tan^2(t))$ over $0\le t\le\frac{\pi}{4}$.
2. With $sec^2(t)=tan^2(t)+1$, we have $x=y+1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Cumulative Review - Review Exercises - Page 719: 34
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