Answer
ellipse, center $(0,0)$, vertices $(0,-5),(0,5)$, foci $(0,-3),(0,3)$
Work Step by Step
1. Given $\frac{y^2}{25}+\frac{x^2}{16}=1$, we can identify it as an ellipse with a vertical major axis, $a=5, b=4$ and $c=\sqrt {a^2-b^2}=3$.
2. We can find its center $(0,0)$, vertices $(0,-5),(0,5)$, foci $(0,-3),(0,3)$
