Answer
parabola, vertex $(0,0)$, focus $(-4,0)$, and directrix $x=4$.
Work Step by Step
1. Given $y^2=-16x$, we can identify it as a parabola opens to the left with $p=4$.
2. We can find its vertex $(0,0)$, focus $(-4,0)$, and directrix $x=4$.
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