Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 647: 83

Answer

$ c=3\sqrt 5\approx6.71, A \approx26.6^\circ, B \approx63.4^\circ$

Work Step by Step

1. Use the Pythagorean Theorem, we have: $c=\sqrt {3^2+6^2}=3\sqrt 5\approx6.71$ 2. And angle $A=tan^{-1}\frac{3}{6}\approx26.6^\circ$ 3. Thus angle $B=90-A\approx63.4^\circ$
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