Answer
$ c=3\sqrt 5\approx6.71, A \approx26.6^\circ, B \approx63.4^\circ$
Work Step by Step
1. Use the Pythagorean Theorem, we have:
$c=\sqrt {3^2+6^2}=3\sqrt 5\approx6.71$
2. And angle $A=tan^{-1}\frac{3}{6}\approx26.6^\circ$
3. Thus angle $B=90-A\approx63.4^\circ$