Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 647: 82

Answer

$\frac{1}{2}$

Work Step by Step

Use the Sum/Difference formula, we can get: $sin80^\circ cos50^\circ-cos80^\circ sin50^\circ=sin(80^\circ-50^\circ)=sin30^\circ=\frac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.