Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.5 The Dot Product - 8.5 Assess Your Understanding - Page 636: 1

Answer

$$c^2=a^2+b^2-2ab \cdot\cos{C} \\ b^2=a^2+c^2-2ac \cdot\cos{B}\\ a^2=b^2+c^2-2bc\cdot \cos{A} \\ $$

Work Step by Step

$$c^2=a^2+b^2-2ab \cdot\cos \ C $$ It can also be represented as: $$a^2=b^2+c^2-2bc\cdot\cos \ A \\ b^2=a^2+c^2-2ac \cdot\cos \ B$$
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