Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 591: 3


$$\tan \theta=\frac{b}{a}.$$

Work Step by Step

We know that $\tan \theta=\frac{y}{x}$. This can also be thought of as $\frac{opposite}{adjacent}$ (recall SOH-CAH-TOA). Thus, we have: $$\tan \theta=\frac{b}{a}.$$
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