Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.1 Polar Cordinates - 8.1 Assess Your Understanding - Page 591: 2

Answer

$9$

Work Step by Step

To complete the square of $x^2 + 6x$, we add ($\frac{1}{2}b)^2$. Here, the "$b$" corresponds to the second coefficient, $6$. Thus, we have: $(\frac{1}{2}\times 6)^2=9$.
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