Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.4 Area of a Triangle - 7.4 Assess Your Understanding - Page 564: 6

Answer

$3$

Work Step by Step

We apply the area formula: $k=\dfrac{1}{2} b \ c \sin A$ Plug in the given data. $k=\dfrac{1}{2} (4)(3) \sin (30^{\circ})=(\dfrac{1}{2}) (4)(3) ( \dfrac{1}{2}) =3$ $[\because \sin 30^{\circ}=\dfrac{1}{2}]$ Thus, the answer is $3$.
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