Answer
$2.83$
Work Step by Step
Based on the given figure, the height is $2sin45^\circ=\sqrt 2$ and the area is $K=\frac{1}{2}(4)(\sqrt 2)=2\sqrt 2\approx2.83$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Section 7.4 Area of a Triangle - 7.4 Assess Your Understanding - Page 564: 5
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